NCERT: Chapter 6: TRIANGLES: EXERCISE 6.6: Question 5 In given figure, AD is a median of a triangle ABC and AM is perpendicular to BC. Prove that: (i) AC^2 = AD^2+BC.DM + (BC/2)^2 (ii) AB^2 = AD^2 -BC.DM + (BC/2)^2 (iii) AC^2+ AB^2 = 2 AD^2 +1/2 BC^2
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